Nth Magical Number — LeetCode 878 Python Solution
HardMathBinary Search
- Problem
- #878
- Pattern
- Monotonic Stack
- Reading time
- 2 min
- Source
- leetcode.com
The problem
A positive integer is magical if it is divisible by either a or b. Given the three integers n, a, and b, return the nth magical number.
Example
- Input
- n = 1, a = 2, b = 3
- Output
- 2
Python solution
Python
class Solution:
def nthMagicalNumber(self, n: int, a: int, b: int) -> int:
mod = 10**9 + 7
c = lcm(a, b)
r = (a + b) * n
return bisect_left(range(r), x=n, key=lambda x: x // a + x // b - x // c) % modComplexity
| Measure | Complexity |
|---|---|
| Time | O(log n) or O(n log n) |
| Space | O(1) auxiliary |
Pattern: Monotonic Stack
Answer "what is the next greater element" for every position in one pass. LeetCode 878. Nth Magical Number is filed here because the reference solution below belongs to the algorithm family this hub collects, even though its LeetCode tags point elsewhere.
The monotonic stack guide has the Python template for the pattern and the 225 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 878. Nth Magical Number?
- LeetCode 878. Nth Magical Number is rated Hard on LeetCode.
- What topics does LeetCode 878. Nth Magical Number cover?
- LeetCode 878. Nth Magical Number is tagged Math and Binary Search on LeetCode.