Valid Perfect Square — LeetCode 367 Python Solution

EasyMathBinary Search
Problem
#367
Reading time
2 min

The problem

Given a positive integer num, return true if num is a perfect square or false otherwise. A perfect square is an integer that is the square of an integer.

Example

Input
num = 16
Output
true
Explanation
We return true because 4 * 4 = 16 and 4 is an integer.

Python solution

Python
class Solution:
    def isPerfectSquare(self, num: int) -> bool:
        l = bisect_left(range(1, num + 1), num, key=lambda x: x * x) + 1
        return l * l == num

Complexity

MeasureComplexity
TimeO(\log n), where n is the given number
SpaceO(1) auxiliary

Pattern: Monotonic Stack

Answer "what is the next greater element" for every position in one pass. LeetCode 367. Valid Perfect Square is filed here because the reference solution below belongs to the algorithm family this hub collects, even though its LeetCode tags point elsewhere.

The monotonic stack guide has the Python template for the pattern and the 225 LeetCode problems that use it.

Related problems

Frequently asked questions

How hard is LeetCode 367. Valid Perfect Square?
LeetCode 367. Valid Perfect Square is rated Easy on LeetCode.
What is the time complexity of LeetCode 367. Valid Perfect Square?
The Python solution on this page runs in O(\log n), where n is the given number.
What is the space complexity of LeetCode 367. Valid Perfect Square?
The Python solution on this page uses O(1) auxiliary space.
What topics does LeetCode 367. Valid Perfect Square cover?
LeetCode 367. Valid Perfect Square is tagged Math and Binary Search on LeetCode.

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