Nth Digit — LeetCode 400 Python Solution
MediumMathBinary Search
- Problem
- #400
- Pattern
- Monotonic Stack
- Reading time
- 2 min
- Source
- leetcode.com
The problem
Given an integer n, return the nth digit of the infinite integer sequence [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ...].
Example
- Input
- n = 3
- Output
- 3
Python solution
Python
class Solution:
def findNthDigit(self, n: int) -> int:
k, cnt = 1, 9
while k * cnt < n:
n -= k * cnt
k += 1
cnt *= 10
num = 10 ** (k - 1) + (n - 1) // k
idx = (n - 1) % k
return int(str(num)[idx])Complexity
| Measure | Complexity |
|---|---|
| Time | O(\log_{10} n) |
| Space | O(1) auxiliary |
Pattern: Monotonic Stack
Answer "what is the next greater element" for every position in one pass. LeetCode 400. Nth Digit is filed here because the reference solution below belongs to the algorithm family this hub collects, even though its LeetCode tags point elsewhere.
The monotonic stack guide has the Python template for the pattern and the 225 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 400. Nth Digit?
- LeetCode 400. Nth Digit is rated Medium on LeetCode.
- What is the time complexity of LeetCode 400. Nth Digit?
- The Python solution on this page runs in O(\log_{10} n).
- What is the space complexity of LeetCode 400. Nth Digit?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 400. Nth Digit cover?
- LeetCode 400. Nth Digit is tagged Math and Binary Search on LeetCode.