Reach a Number — LeetCode 754 Python Solution
MediumMathBinary Search
- Problem
- #754
- Pattern
- Monotonic Stack
- Reading time
- 2 min
- Source
- leetcode.com
The problem
You are standing at position 0 on an infinite number line. There is a destination at position target.
Example
- Input
- target = 2
- Output
- 3
- Explanation
- On the 1st move, we step from 0 to 1 (1 step).
Python solution
Python
class Solution:
def reachNumber(self, target: int) -> int:
target = abs(target)
s = k = 0
while 1:
if s >= target and (s - target) % 2 == 0:
return k
k += 1
s += kComplexity
| Measure | Complexity |
|---|---|
| Time | O(\sqrt{\left | \textit{target} \right | }) |
| Space | O(1) auxiliary |
Pattern: Monotonic Stack
Answer "what is the next greater element" for every position in one pass. LeetCode 754. Reach a Number is filed here because the reference solution below belongs to the algorithm family this hub collects, even though its LeetCode tags point elsewhere.
The monotonic stack guide has the Python template for the pattern and the 225 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 754. Reach a Number?
- LeetCode 754. Reach a Number is rated Medium on LeetCode.
- What is the time complexity of LeetCode 754. Reach a Number?
- The Python solution on this page runs in O(\sqrt{\left | \textit{target} \right | }).
- What is the space complexity of LeetCode 754. Reach a Number?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 754. Reach a Number cover?
- LeetCode 754. Reach a Number is tagged Math and Binary Search on LeetCode.