Count Integers With Even Digit Sum — LeetCode 2180 Python Solution

EasyMathSimulation
Problem
#2180
Reading time
2 min

The problem

Given a positive integer num, return the number of positive integers less than or equal to num whose digit sums are even. The digit sum of a positive integer is the sum of all its digits.

Example

Input
num = 4
Output
2
Explanation
The only integers less than or equal to 4 whose digit sums are even are 2 and 4.

Python solution

Python
class Solution:
    def countEven(self, num: int) -> int:
        ans = 0
        for x in range(1, num + 1):
            s = 0
            while x:
                s += x % 10
                x //= 10
            ans += s % 2 == 0
        return ans

Complexity

MeasureComplexity
TimeO(n) or O(1)
SpaceO(1) auxiliary

Pattern: Math and Number Theory

Find the closed form, the invariant, or the modular identity — and skip the loop entirely. LeetCode 2180. Count Integers With Even Digit Sum is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Math.

The math and number theory guide has the Python template for the pattern and the 485 LeetCode problems that use it.

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Frequently asked questions

How hard is LeetCode 2180. Count Integers With Even Digit Sum?
LeetCode 2180. Count Integers With Even Digit Sum is rated Easy on LeetCode.
What topics does LeetCode 2180. Count Integers With Even Digit Sum cover?
LeetCode 2180. Count Integers With Even Digit Sum is tagged Math and Simulation on LeetCode.

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