EasyNo. 2180

Count Integers With Even Digit Sum — LeetCode 2180 Python Solution

Topics
Math, Simulation
Reading time
2 min

The problem

Given a positive integer num, return the number of positive integers less than or equal to num whose digit sums are even. The digit sum of a positive integer is the sum of all its digits.

Example

Input
num = 4
Output
2
Explanation
The only integers less than or equal to 4 whose digit sums are even are 2 and 4.

Python solution

PythonSolution
class Solution:
    def countEven(self, num: int) -> int:
        ans = 0
        for x in range(1, num + 1):
            s = 0
            while x:
                s += x % 10
                x //= 10
            ans += s % 2 == 0
        return ans

Complexity

Time
O(n) or O(1)
Space · auxiliary
O(1)

Pattern: Math and Number Theory

Find the closed form, the invariant, or the modular identity — and skip the loop entirely. LeetCode 2180. Count Integers With Even Digit Sum is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Math.

The math and number theory guide has the Python template for the pattern and the 485 LeetCode problems that use it.

Related problems

Related problems
No.ProblemDifficulty
2177Find Three Consecutive Integers That Sum to a Given NumberMedium
0043Multiply StringsMedium
0258Add DigitsEasy
0412Fizz BuzzEasy
0415Add StringsEasy
0537Complex Number MultiplicationMedium

Frequently asked questions

How hard is LeetCode 2180. Count Integers With Even Digit Sum?

LeetCode 2180. Count Integers With Even Digit Sum is rated Easy on LeetCode.

What topics does LeetCode 2180. Count Integers With Even Digit Sum cover?

LeetCode 2180. Count Integers With Even Digit Sum is tagged Math and Simulation on LeetCode.

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