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Leetcode #2177: Find Three Consecutive Integers That Sum to a Given Number

In this guide, we solve Leetcode #2177 Find Three Consecutive Integers That Sum to a Given Number in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

Given an integer num, return three consecutive integers (as a sorted array) that sum to num. If num cannot be expressed as the sum of three consecutive integers, return an empty array.

Quick Facts

  • Difficulty: Medium
  • Premium: No
  • Tags: Math, Simulation

Intuition

There is a mathematical invariant or formula that directly leads to the result.

Using math avoids unnecessary loops and reduces complexity.

Approach

Derive the formula or update rule, then compute the answer directly.

Handle edge cases like overflow or zero carefully.

Steps:

  • Identify the math relationship.
  • Compute the result with a loop or formula.
  • Handle edge cases.

Example

Input: num = 33 Output: [10,11,12] Explanation: 33 can be expressed as 10 + 11 + 12 = 33. 10, 11, 12 are 3 consecutive integers, so we return [10, 11, 12].

Python Solution

class Solution: def sumOfThree(self, num: int) -> List[int]: x, mod = divmod(num, 3) return [] if mod else [x - 1, x, x + 1]

Complexity

The time complexity is O(1)O(1)O(1), and the space complexity is O(1)O(1)O(1). The space complexity is O(1)O(1)O(1).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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