Add Digits — LeetCode 258 Python Solution
EasyMathNumber TheorySimulation
- Problem
- #258
- Pattern
- Math and Number Theory
- Reading time
- 2 min
- Source
- leetcode.com
The problem
Given an integer num, repeatedly add all its digits until the result has only one digit, and return it.
Example
- Input
- num = 38
- Output
- 2
- Explanation
- The process is
Python solution
Python
class Solution:
def addDigits(self, num: int) -> int:
return 0 if num == 0 else (num - 1) % 9 + 1Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) or O(1) |
| Space | O(1) auxiliary |
Pattern: Math and Number Theory
Find the closed form, the invariant, or the modular identity — and skip the loop entirely. LeetCode 258. Add Digits is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Math and Number Theory.
The math and number theory guide has the Python template for the pattern and the 485 LeetCode problems that use it.
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Frequently asked questions
- How hard is LeetCode 258. Add Digits?
- LeetCode 258. Add Digits is rated Easy on LeetCode.
- What topics does LeetCode 258. Add Digits cover?
- LeetCode 258. Add Digits is tagged Math, Number Theory and Simulation on LeetCode.