Best Time to Buy and Sell Stock III — LeetCode 123 Python Solution
- Problem
- #123
- Pattern
- Dynamic Programming
- Reading time
- 2 min
- Source
- leetcode.com
The problem
You are given an array prices where prices[i] is the price of a given stock on the ith day. Find the maximum profit you can achieve.
Example
- Input
- prices = [3,3,5,0,0,3,1,4]
- Output
- 6
- Explanation
- Buy on day 4 (price = 0) and sell on day 6 (price = 3), profit = 3-0 = 3.
Python solution
class Solution:
def maxProfit(self, prices: List[int]) -> int:
# 第一次买入,第一次卖出,第二次买入,第二次卖出
f1, f2, f3, f4 = -prices[0], 0, -prices[0], 0
for price in prices[1:]:
f1 = max(f1, -price)
f2 = max(f2, f1 + price)
f3 = max(f3, f2 - price)
f4 = max(f4, f3 + price)
return f4Complexity
| Measure | Complexity |
|---|---|
| Time | O(n), where n is the length of the `prices` array |
| Space | O(1) auxiliary |
Pattern: Dynamic Programming
Define a state, write the transition, and stop recomputing the same subproblem. LeetCode 123. Best Time to Buy and Sell Stock III is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Dynamic Programming.
The dynamic programming guide has the Python template for the pattern and the 481 LeetCode problems that use it.
Related problems
On a study list
This problem is on Top Interview 150.
Frequently asked questions
- How hard is LeetCode 123. Best Time to Buy and Sell Stock III?
- LeetCode 123. Best Time to Buy and Sell Stock III is rated Hard on LeetCode.
- What is the time complexity of LeetCode 123. Best Time to Buy and Sell Stock III?
- The Python solution on this page runs in O(n), where n is the length of the `prices` array.
- What is the space complexity of LeetCode 123. Best Time to Buy and Sell Stock III?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 123. Best Time to Buy and Sell Stock III cover?
- LeetCode 123. Best Time to Buy and Sell Stock III is tagged Array and Dynamic Programming on LeetCode.