Jump Game II — LeetCode 45 Python Solution
MediumGreedyArrayDynamic Programming
- Problem
- #45
- Pattern
- Greedy
- Reading time
- 2 min
- Source
- leetcode.com
The problem
You are given a 0-indexed array of integers nums of length n. You are initially positioned at index 0.
Example
- Input
- nums = [2,3,1,1,4]
- Output
- 2
- Explanation
- The minimum number of jumps to reach the last index is 2. Jump 1 step from index 0 to 1, then 3 steps to the last index.
Python solution
Python
class Solution:
def jump(self, nums: List[int]) -> int:
ans = mx = last = 0
for i, x in enumerate(nums[:-1]):
mx = max(mx, i + x)
if last == i:
ans += 1
last = mx
return ansComplexity
| Measure | Complexity |
|---|---|
| Time | O(n), where n is the length of the array |
| Space | O(1) auxiliary |
Pattern: Greedy
Take the locally best option every time — when you can prove that never costs you later. LeetCode 45. Jump Game II is filed here because LeetCode tags it Greedy, which is the vocabulary this hub collects.
The greedy guide has the Python template for the pattern and the 346 LeetCode problems that use it.
Related problems
On study lists
This problem is on NeetCode 150 and Top Interview 150.
Frequently asked questions
- How hard is LeetCode 45. Jump Game II?
- LeetCode 45. Jump Game II is rated Medium on LeetCode.
- What is the time complexity of LeetCode 45. Jump Game II?
- The Python solution on this page runs in O(n), where n is the length of the array.
- What is the space complexity of LeetCode 45. Jump Game II?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 45. Jump Game II cover?
- LeetCode 45. Jump Game II is tagged Greedy, Array and Dynamic Programming on LeetCode.