Greatest Common Divisor of Strings — LeetCode 1071 Python Solution

EasyMathString
Problem
#1071
Reading time
2 min

The problem

For two strings s and t, we say "t divides s" if and only if s = t + t + t + ... + t + t (i.e., t is concatenated with itself one or more times).

Python solution

Python
class Solution:
    def gcdOfStrings(self, str1: str, str2: str) -> str:
        def check(a, b):
            c = ""
            while len(c) < len(b):
                c += a
            return c == b

        for i in range(min(len(str1), len(str2)), 0, -1):
            t = str1[:i]
            if check(t, str1) and check(t, str2):
                return t
        return ''

Complexity

MeasureComplexity
TimeO(n) or O(1)
SpaceO(1) auxiliary

Pattern: Math and Number Theory

Find the closed form, the invariant, or the modular identity — and skip the loop entirely. LeetCode 1071. Greatest Common Divisor of Strings is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Math.

The math and number theory guide has the Python template for the pattern and the 485 LeetCode problems that use it.

Related problems

On a study list

This problem is on LeetCode 75.

Frequently asked questions

How hard is LeetCode 1071. Greatest Common Divisor of Strings?
LeetCode 1071. Greatest Common Divisor of Strings is rated Easy on LeetCode.
What topics does LeetCode 1071. Greatest Common Divisor of Strings cover?
LeetCode 1071. Greatest Common Divisor of Strings is tagged Math and String on LeetCode.

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