Greatest Common Divisor of Strings — LeetCode 1071 Python Solution
- Problem
- #1071
- Pattern
- Math and Number Theory
- Reading time
- 2 min
- Source
- leetcode.com
The problem
For two strings s and t, we say "t divides s" if and only if s = t + t + t + ... + t + t (i.e., t is concatenated with itself one or more times).
Python solution
class Solution:
def gcdOfStrings(self, str1: str, str2: str) -> str:
def check(a, b):
c = ""
while len(c) < len(b):
c += a
return c == b
for i in range(min(len(str1), len(str2)), 0, -1):
t = str1[:i]
if check(t, str1) and check(t, str2):
return t
return ''Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) or O(1) |
| Space | O(1) auxiliary |
Pattern: Math and Number Theory
Find the closed form, the invariant, or the modular identity — and skip the loop entirely. LeetCode 1071. Greatest Common Divisor of Strings is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Math.
The math and number theory guide has the Python template for the pattern and the 485 LeetCode problems that use it.
Related problems
On a study list
This problem is on LeetCode 75.
Frequently asked questions
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- LeetCode 1071. Greatest Common Divisor of Strings is tagged Math and String on LeetCode.