Video Stitching — LeetCode 1024 Python Solution
MediumGreedyArrayDynamic Programming
- Problem
- #1024
- Pattern
- Greedy
- Reading time
- 3 min
- Source
- leetcode.com
The problem
You are given a series of video clips from a sporting event that lasted time seconds. These video clips can be overlapping with each other and have varying lengths.
Example
- Input
- clips = [[0,2],[4,6],[8,10],[1,9],[1,5],[5,9]], time = 10
- Output
- 3
- Explanation
- We take the clips [0,2], [8,10], [1,9]; a total of 3 clips.
Python solution
Python
class Solution:
def videoStitching(self, clips: List[List[int]], time: int) -> int:
last = [0] * time
for a, b in clips:
if a < time:
last[a] = max(last[a], b)
ans = mx = pre = 0
for i, v in enumerate(last):
mx = max(mx, v)
if mx <= i:
return -1
if pre == i:
ans += 1
pre = mx
return ansComplexity
| Measure | Complexity |
|---|---|
| Time | O(n+m) |
| Space | O(m) auxiliary |
Pattern: Greedy
Take the locally best option every time — when you can prove that never costs you later. LeetCode 1024. Video Stitching is filed here because LeetCode tags it Greedy, which is the vocabulary this hub collects.
The greedy guide has the Python template for the pattern and the 346 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1024. Video Stitching?
- LeetCode 1024. Video Stitching is rated Medium on LeetCode.
- What is the time complexity of LeetCode 1024. Video Stitching?
- The Python solution on this page runs in O(n+m).
- What is the space complexity of LeetCode 1024. Video Stitching?
- The Python solution on this page uses O(m) auxiliary space.
- What topics does LeetCode 1024. Video Stitching cover?
- LeetCode 1024. Video Stitching is tagged Greedy, Array and Dynamic Programming on LeetCode.