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Leetcode #958: Check Completeness of a Binary Tree

In this guide, we solve Leetcode #958 Check Completeness of a Binary Tree in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

Given the root of a binary tree, determine if it is a complete binary tree. In a complete binary tree, every level, except possibly the last, is completely filled, and all nodes in the last level are as far left as possible.

Quick Facts

  • Difficulty: Medium
  • Premium: No
  • Tags: Tree, Breadth-First Search, Binary Tree

Intuition

We need level-by-level exploration or shortest steps, which is ideal for BFS.

A queue naturally models the frontier of the search.

Approach

Push initial nodes into a queue and expand in layers.

Track visited nodes to prevent cycles.

Steps:

  • Initialize queue with start nodes.
  • Process level by level.
  • Track visited nodes.

Example

Input: root = [1,2,3,4,5,6] Output: true Explanation: Every level before the last is full (ie. levels with node-values {1} and {2, 3}), and all nodes in the last level ({4, 5, 6}) are as far left as possible.

Python Solution

# Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def isCompleteTree(self, root: TreeNode) -> bool: q = deque([root]) while q: node = q.popleft() if node is None: break q.append(node.left) q.append(node.right) return all(node is None for node in q)

Complexity

The time complexity is O(V+E). The space complexity is O(V).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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