Subsets II — LeetCode 90 Python Solution
- Problem
- #90
- Pattern
- Backtracking
- Reading time
- 3 min
- Source
- leetcode.com
The problem
Given an integer array nums that may contain duplicates, return all possible subsets (the power set). The solution set must not contain duplicate subsets.
Example
- Input
- nums = [1,2,2]
- Output
- [[],[1],[1,2],[1,2,2],[2],[2,2]]
Python solution
class Solution:
def subsetsWithDup(self, nums: List[int]) -> List[List[int]]:
def dfs(i: int):
if i == len(nums):
ans.append(t[:])
return
t.append(nums[i])
dfs(i + 1)
x = t.pop()
while i + 1 < len(nums) and nums[i + 1] == x:
i += 1
dfs(i + 1)
nums.sort()
ans = []
t = []
dfs(0)
return ansComplexity
| Measure | Complexity |
|---|---|
| Time | O(n \times 2^n) |
| Space | O(n) auxiliary |
Pattern: Backtracking
Build candidates one choice at a time and abandon a branch the moment it cannot work. LeetCode 90. Subsets II is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Backtracking.
The backtracking guide has the Python template for the pattern and the 105 LeetCode problems that use it.
Related problems
On a study list
This problem is on NeetCode 150.
Frequently asked questions
- How hard is LeetCode 90. Subsets II?
- LeetCode 90. Subsets II is rated Medium on LeetCode.
- What is the time complexity of LeetCode 90. Subsets II?
- The Python solution on this page runs in O(n \times 2^n).
- What is the space complexity of LeetCode 90. Subsets II?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 90. Subsets II cover?
- LeetCode 90. Subsets II is tagged Bit Manipulation, Array and Backtracking on LeetCode.