Subsets — LeetCode 78 Python Solution
- Problem
- #78
- Pattern
- Backtracking
- Reading time
- 3 min
- Source
- leetcode.com
The problem
Given an integer array nums of unique elements, return all possible subsets (the power set). The solution set must not contain duplicate subsets.
Example
- Input
- nums = [1,2,3]
- Output
- [[],[1],[2],[1,2],[3],[1,3],[2,3],[1,2,3]]
Python solution
class Solution:
def subsets(self, nums: List[int]) -> List[List[int]]:
def dfs(i: int):
if i == len(nums):
ans.append(t[:])
return
dfs(i + 1)
t.append(nums[i])
dfs(i + 1)
t.pop()
ans = []
t = []
dfs(0)
return ansComplexity
| Measure | Complexity |
|---|---|
| Time | O(n \times 2^n) |
| Space | O(n) auxiliary |
Pattern: Backtracking
Build candidates one choice at a time and abandon a branch the moment it cannot work. LeetCode 78. Subsets is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Backtracking.
The backtracking guide has the Python template for the pattern and the 105 LeetCode problems that use it.
Related problems
On study lists
This problem is on NeetCode 150 and Grind 75.
Frequently asked questions
- How hard is LeetCode 78. Subsets?
- LeetCode 78. Subsets is rated Medium on LeetCode.
- What is the time complexity of LeetCode 78. Subsets?
- The Python solution on this page runs in O(n \times 2^n).
- What is the space complexity of LeetCode 78. Subsets?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 78. Subsets cover?
- LeetCode 78. Subsets is tagged Bit Manipulation, Array and Backtracking on LeetCode.