Orderly Queue — LeetCode 899 Python Solution
HardMathStringSorting
- Problem
- #899
- Pattern
- Sorting
- Reading time
- 2 min
- Source
- leetcode.com
The problem
You are given a string s and an integer k. You can choose one of the first k letters of s and append it at the end of the string.
Example
- Input
- s = "cba", k = 1
- Output
- "acb"
- Explanation
- In the first move, we move the 1st character 'c' to the end, obtaining the string "bac".
Python solution
Python
class Solution:
def orderlyQueue(self, s: str, k: int) -> str:
if k == 1:
ans = s
for _ in range(len(s) - 1):
s = s[1:] + s[0]
ans = min(ans, s)
return ans
return "".join(sorted(s))Complexity
| Measure | Complexity |
|---|---|
| Time | O(n^2) |
| Space | O(n) auxiliary |
Pattern: Sorting
Spend O(n log n) once to buy an ordering that makes the rest of the problem trivial. LeetCode 899. Orderly Queue is filed here because LeetCode tags it Sorting, which is the vocabulary this hub collects.
The sorting guide has the Python template for the pattern and the 401 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 899. Orderly Queue?
- LeetCode 899. Orderly Queue is rated Hard on LeetCode.
- What is the time complexity of LeetCode 899. Orderly Queue?
- The Python solution on this page runs in O(n^2).
- What is the space complexity of LeetCode 899. Orderly Queue?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 899. Orderly Queue cover?
- LeetCode 899. Orderly Queue is tagged Math, String and Sorting on LeetCode.