Sum of Subsequence Widths — LeetCode 891 Python Solution
HardArrayMathSorting
- Problem
- #891
- Pattern
- Sorting
- Reading time
- 2 min
- Source
- leetcode.com
The problem
The width of a sequence is the difference between the maximum and minimum elements in the sequence. Given an array of integers nums, return the sum of the widths of all the non-empty subsequences of nums.
Example
- Input
- nums = [2,1,3]
- Output
- 6
- Explanation
- The subsequences are [1], [2], [3], [2,1], [2,3], [1,3], [2,1,3].
Python solution
Python
class Solution:
def sumSubseqWidths(self, nums: List[int]) -> int:
mod = 10**9 + 7
nums.sort()
ans, p = 0, 1
for i, v in enumerate(nums):
ans = (ans + (v - nums[-i - 1]) * p) % mod
p = (p << 1) % mod
return ansComplexity
| Measure | Complexity |
|---|---|
| Time | O(n log n) |
| Space | O(1) to O(n) auxiliary |
Pattern: Sorting
Spend O(n log n) once to buy an ordering that makes the rest of the problem trivial. LeetCode 891. Sum of Subsequence Widths is filed here because LeetCode tags it Sorting, which is the vocabulary this hub collects.
The sorting guide has the Python template for the pattern and the 401 LeetCode problems that use it.
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Frequently asked questions
- How hard is LeetCode 891. Sum of Subsequence Widths?
- LeetCode 891. Sum of Subsequence Widths is rated Hard on LeetCode.
- What topics does LeetCode 891. Sum of Subsequence Widths cover?
- LeetCode 891. Sum of Subsequence Widths is tagged Array, Math and Sorting on LeetCode.