Domino and Tromino Tiling — LeetCode 790 Python Solution

MediumDynamic Programming
Problem
#790
Reading time
2 min

The problem

You have two types of tiles: a 2 x 1 domino shape and a tromino shape. You may rotate these shapes.

Example

Input
n = 3
Output
5
Explanation
The five different ways are shown above.

Python solution

Python
class Solution:
    def numTilings(self, n: int) -> int:
        f = [1, 0, 0, 0]
        mod = 10**9 + 7
        for i in range(1, n + 1):
            g = [0] * 4
            g[0] = (f[0] + f[1] + f[2] + f[3]) % mod
            g[1] = (f[2] + f[3]) % mod
            g[2] = (f[1] + f[3]) % mod
            g[3] = f[0]
            f = g
        return f[0]

Complexity

MeasureComplexity
TimeO(n)
SpaceO(1) auxiliary

Pattern: Dynamic Programming

Define a state, write the transition, and stop recomputing the same subproblem. LeetCode 790. Domino and Tromino Tiling is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Dynamic Programming.

The dynamic programming guide has the Python template for the pattern and the 481 LeetCode problems that use it.

Related problems

On a study list

This problem is on LeetCode 75.

Frequently asked questions

How hard is LeetCode 790. Domino and Tromino Tiling?
LeetCode 790. Domino and Tromino Tiling is rated Medium on LeetCode.
What is the time complexity of LeetCode 790. Domino and Tromino Tiling?
The Python solution on this page runs in O(n).
What is the space complexity of LeetCode 790. Domino and Tromino Tiling?
The Python solution on this page uses O(1) auxiliary space.
What topics does LeetCode 790. Domino and Tromino Tiling cover?
LeetCode 790. Domino and Tromino Tiling is tagged Dynamic Programming on LeetCode.

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