Target Sum — LeetCode 494 Python Solution
- Problem
- #494
- Pattern
- Backtracking
- Reading time
- 3 min
- Source
- leetcode.com
The problem
You are given an integer array nums and an integer target. You want to build an expression out of nums by adding one of the symbols '+' and '-' before each integer in nums and then concatenate all the integers.
Example
- Input
- nums = [1,1,1,1,1], target = 3
- Output
- 5
- Explanation
- There are 5 ways to assign symbols to make the sum of nums be target 3.
Python solution
class Solution:
def findTargetSumWays(self, nums: List[int], target: int) -> int:
s = sum(nums)
if s < target or (s - target) % 2:
return 0
m, n = len(nums), (s - target) // 2
f = [[0] * (n + 1) for _ in range(m + 1)]
f[0][0] = 1
for i, x in enumerate(nums, 1):
for j in range(n + 1):
f[i][j] = f[i - 1][j]
if j >= x:
f[i][j] += f[i - 1][j - x]
return f[m][n]Complexity
| Measure | Complexity |
|---|---|
| Time | O(m \times n) |
| Space | O(m \times n) auxiliary |
Pattern: Backtracking
Build candidates one choice at a time and abandon a branch the moment it cannot work. LeetCode 494. Target Sum is filed here because LeetCode tags it Backtracking, which is the vocabulary this hub collects.
The backtracking guide has the Python template for the pattern and the 105 LeetCode problems that use it.
Related problems
On a study list
This problem is on NeetCode 150.
Frequently asked questions
- How hard is LeetCode 494. Target Sum?
- LeetCode 494. Target Sum is rated Medium on LeetCode.
- What is the time complexity of LeetCode 494. Target Sum?
- The Python solution on this page runs in O(m \times n).
- What is the space complexity of LeetCode 494. Target Sum?
- The Python solution on this page uses O(m \times n) auxiliary space.
- What topics does LeetCode 494. Target Sum cover?
- LeetCode 494. Target Sum is tagged Array, Dynamic Programming and Backtracking on LeetCode.