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Leetcode #2997: Minimum Number of Operations to Make Array XOR Equal to K

In this guide, we solve Leetcode #2997 Minimum Number of Operations to Make Array XOR Equal to K in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

You are given a 0-indexed integer array nums and a positive integer k. You can apply the following operation on the array any number of times: Choose any element of the array and flip a bit in its binary representation.

Quick Facts

  • Difficulty: Medium
  • Premium: No
  • Tags: Bit Manipulation, Array

Intuition

The problem structure lets us track state with bitwise operations.

Bit operations are constant time and avoid extra memory.

Approach

Apply XOR/AND/OR and shifts to maintain the required invariant.

Aggregate the result in a single pass.

Steps:

  • Identify a bitwise invariant.
  • Combine values with bit operations.
  • Return the aggregated result.

Example

Input: nums = [2,1,3,4], k = 1 Output: 2 Explanation: We can do the following operations: - Choose element 2 which is 3 == (011)2, we flip the first bit and we obtain (010)2 == 2. nums becomes [2,1,2,4]. - Choose element 0 which is 2 == (010)2, we flip the third bit and we obtain (110)2 = 6. nums becomes [6,1,2,4]. The XOR of elements of the final array is (6 XOR 1 XOR 2 XOR 4) == 1 == k. It can be shown that we cannot make the XOR equal to k in less than 2 operations.

Python Solution

class Solution: def minOperations(self, nums: List[int], k: int) -> int: return reduce(xor, nums, k).bit_count()

Complexity

The time complexity is O(n)O(n)O(n), where nnn is the length of the array numsnumsnums. The space complexity is O(1)O(1)O(1).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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