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Leetcode #2632: Curry

In this guide, we solve Leetcode #2632 Curry in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

Given a function fn, return a curried version of that function. A curried function is a function that accepts fewer or an equal number of parameters as the original function and returns either another curried function or the same value the original function would have returned.

Quick Facts

  • Difficulty: Medium
  • Premium: Yes
  • Tags: JavaScript

Intuition

The constraints allow a direct scan that keeps only the essential state.

By translating the requirements into a clean loop, the logic stays easy to reason about.

Approach

Iterate through the data once, updating the state needed to compute the answer.

Return the final state after the traversal is complete.

Steps:

  • Parse the input.
  • Iterate and update state.
  • Return the computed answer.

Example

Input: fn = function sum(a, b, c) { return a + b + c; } inputs = [[1],[2],[3]] Output: 6 Explanation: The code being executed is: const curriedSum = curry(fn); curriedSum(1)(2)(3) === 6; curriedSum(1)(2)(3) should return the same value as sum(1, 2, 3).

Python Solution

# TODO: add Python solution

Complexity

The time complexity is O(n). The space complexity is O(1) to O(n).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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