Minimum Replacements to Sort the Array — LeetCode 2366 Python Solution
HardGreedyArrayMath
- Problem
- #2366
- Pattern
- Greedy
- Reading time
- 3 min
- Source
- leetcode.com
The problem
You are given a 0-indexed integer array nums. In one operation you can replace any element of the array with any two elements that sum to it.
Example
- Input
- nums = [3,9,3]
- Output
- 2
- Explanation
- Here are the steps to sort the array in non-decreasing order:
Python solution
Python
class Solution:
def minimumReplacement(self, nums: List[int]) -> int:
ans = 0
n = len(nums)
mx = nums[-1]
for i in range(n - 2, -1, -1):
if nums[i] <= mx:
mx = nums[i]
continue
k = (nums[i] + mx - 1) // mx
ans += k - 1
mx = nums[i] // k
return ansComplexity
| Measure | Complexity |
|---|---|
| Time | O(n), where n is the length of the array nums |
| Space | O(1) auxiliary |
Pattern: Greedy
Take the locally best option every time — when you can prove that never costs you later. LeetCode 2366. Minimum Replacements to Sort the Array is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Greedy.
The greedy guide has the Python template for the pattern and the 346 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 2366. Minimum Replacements to Sort the Array?
- LeetCode 2366. Minimum Replacements to Sort the Array is rated Hard on LeetCode.
- What is the time complexity of LeetCode 2366. Minimum Replacements to Sort the Array?
- The Python solution on this page runs in O(n), where n is the length of the array nums.
- What is the space complexity of LeetCode 2366. Minimum Replacements to Sort the Array?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 2366. Minimum Replacements to Sort the Array cover?
- LeetCode 2366. Minimum Replacements to Sort the Array is tagged Greedy, Array and Math on LeetCode.