Minimum Cost to Move Chips to The Same Position — LeetCode 1217 Python Solution
EasyGreedyArrayMath
- Problem
- #1217
- Pattern
- Greedy
- Reading time
- 2 min
- Source
- leetcode.com
The problem
We have n chips, where the position of the ith chip is position[i]. We need to move all the chips to the same position.
Example
- Input
- position = [1,2,3]
- Output
- 1
- Explanation
- First step: Move the chip at position 3 to position 1 with cost = 0.
Python solution
Python
class Solution:
def minCostToMoveChips(self, position: List[int]) -> int:
a = sum(p % 2 for p in position)
b = len(position) - a
return min(a, b)Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(1) auxiliary |
Pattern: Greedy
Take the locally best option every time — when you can prove that never costs you later. LeetCode 1217. Minimum Cost to Move Chips to The Same Position is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Greedy.
The greedy guide has the Python template for the pattern and the 346 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1217. Minimum Cost to Move Chips to The Same Position?
- LeetCode 1217. Minimum Cost to Move Chips to The Same Position is rated Easy on LeetCode.
- What is the time complexity of LeetCode 1217. Minimum Cost to Move Chips to The Same Position?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 1217. Minimum Cost to Move Chips to The Same Position?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 1217. Minimum Cost to Move Chips to The Same Position cover?
- LeetCode 1217. Minimum Cost to Move Chips to The Same Position is tagged Greedy, Array and Math on LeetCode.