Remove Digit From Number to Maximize Result — LeetCode 2259 Python Solution
- Problem
- #2259
- Pattern
- Greedy
- Reading time
- 2 min
- Source
- leetcode.com
The problem
You are given a string number representing a positive integer and a character digit. Return the resulting string after removing exactly one occurrence of digit from number such that the value of the resulting string in decimal form is maximized.
Example
- Input
- number = "123", digit = "3"
- Output
- "12"
- Explanation
- There is only one '3' in "123". After removing '3', the result is "12".
Python solution
class Solution:
def removeDigit(self, number: str, digit: str) -> str:
return max(
number[:i] + number[i + 1 :] for i, d in enumerate(number) if d == digit
)Complexity
| Measure | Complexity |
|---|---|
| Time | O(n^2) |
| Space | O(n) auxiliary |
Pattern: Greedy
Take the locally best option every time — when you can prove that never costs you later. LeetCode 2259. Remove Digit From Number to Maximize Result is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Greedy.
The greedy guide has the Python template for the pattern and the 346 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 2259. Remove Digit From Number to Maximize Result?
- LeetCode 2259. Remove Digit From Number to Maximize Result is rated Easy on LeetCode.
- What is the time complexity of LeetCode 2259. Remove Digit From Number to Maximize Result?
- The Python solution on this page runs in O(n^2).
- What is the space complexity of LeetCode 2259. Remove Digit From Number to Maximize Result?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 2259. Remove Digit From Number to Maximize Result cover?
- LeetCode 2259. Remove Digit From Number to Maximize Result is tagged Greedy, String and Enumeration on LeetCode.