Smallest Index With Equal Value — LeetCode 2057 Python Solution

EasyArray
Problem
#2057
Reading time
2 min

The problem

Given a 0-indexed integer array nums, return the smallest index i of nums such that i mod 10 == nums[i], or -1 if such index does not exist. x mod y denotes the remainder when x is divided by y.

Example

Input
nums = [0,1,2]
Output
0
Explanation
i=0: 0 mod 10 = 0 == nums[0].

Python solution

Python
class Solution:
    def smallestEqual(self, nums: List[int]) -> int:
        for i, x in enumerate(nums):
            if i % 10 == x:
                return i
        return -1

Complexity

MeasureComplexity
TimeO(n), where n is the length of the array
SpaceO(1) auxiliary

Related problems

Frequently asked questions

How hard is LeetCode 2057. Smallest Index With Equal Value?
LeetCode 2057. Smallest Index With Equal Value is rated Easy on LeetCode.
What is the time complexity of LeetCode 2057. Smallest Index With Equal Value?
The Python solution on this page runs in O(n), where n is the length of the array.
What is the space complexity of LeetCode 2057. Smallest Index With Equal Value?
The Python solution on this page uses O(1) auxiliary space.
What topics does LeetCode 2057. Smallest Index With Equal Value cover?
LeetCode 2057. Smallest Index With Equal Value is tagged Array on LeetCode.

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