Binary Tree Right Side View — LeetCode 199 Python Solution
- Problem
- #199
- Pattern
- Tree Traversal
- Reading time
- 4 min
- Source
- leetcode.com
The problem
Given the root of a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom.
Python solution
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def rightSideView(self, root: Optional[TreeNode]) -> List[int]:
ans = []
if root is None:
return ans
q = deque([root])
while q:
ans.append(q[0].val)
for _ in range(len(q)):
node = q.popleft()
if node.right:
q.append(node.right)
if node.left:
q.append(node.left)
return ansComplexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(n) auxiliary |
Pattern: Tree Traversal
Choose the order — preorder, inorder, postorder, level — and the problem solves itself. LeetCode 199. Binary Tree Right Side View is filed here because LeetCode tags it Tree and Binary Tree, which is the vocabulary this hub collects.
The tree traversal guide has the Python template for the pattern and the 225 LeetCode problems that use it.
Related problems
On study lists
This problem is on NeetCode 150, Grind 75, LeetCode 75 and Top Interview 150.
Frequently asked questions
- How hard is LeetCode 199. Binary Tree Right Side View?
- LeetCode 199. Binary Tree Right Side View is rated Medium on LeetCode.
- What is the time complexity of LeetCode 199. Binary Tree Right Side View?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 199. Binary Tree Right Side View?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 199. Binary Tree Right Side View cover?
- LeetCode 199. Binary Tree Right Side View is tagged Tree, Depth-First Search, Breadth-First Search and Binary Tree on LeetCode.