Sum of Digits of String After Convert — LeetCode 1945 Python Solution
- Problem
- #1945
- Pattern
- Hash Map
- Reading time
- 2 min
- Source
- leetcode.com
The problem
You are given a string s consisting of lowercase English letters, and an integer k. Your task is to convert the string into an integer by a special process, and then transform it by summing its digits repeatedly k times.
Python solution
class Solution:
def getLucky(self, s: str, k: int) -> int:
s = ''.join(str(ord(c) - ord('a') + 1) for c in s)
for _ in range(k):
t = sum(int(c) for c in s)
s = str(t)
return int(s)Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(n) auxiliary |
Pattern: Hash Map
Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 1945. Sum of Digits of String After Convert is filed here because the reference solution below belongs to the algorithm family this hub collects, even though its LeetCode tags point elsewhere.
The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1945. Sum of Digits of String After Convert?
- LeetCode 1945. Sum of Digits of String After Convert is rated Easy on LeetCode.
- What is the time complexity of LeetCode 1945. Sum of Digits of String After Convert?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 1945. Sum of Digits of String After Convert?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 1945. Sum of Digits of String After Convert cover?
- LeetCode 1945. Sum of Digits of String After Convert is tagged String and Simulation on LeetCode.