Robot Return to Origin — LeetCode 657 Python Solution

EasyStringSimulation
Problem
#657
Pattern
Hash Map
Reading time
3 min

The problem

There is a robot starting at the position (0, 0), the origin, on a 2D plane. Given a sequence of its moves, judge if this robot ends up at (0, 0) after it completes its moves.

Example

Input
moves = "UD"
Output
true
Explanation
The robot moves up once, and then down once. All moves have the same magnitude, so it ended up at the origin where it started. Therefore, we return true.

Python solution

Python
class Solution:
    def judgeCircle(self, moves: str) -> bool:
        x = y = 0
        for c in moves:
            match c:
                case "U":
                    y += 1
                case "D":
                    y -= 1
                case "L":
                    x -= 1
                case "R":
                    x += 1
        return x == 0 and y == 0

Complexity

MeasureComplexity
TimeO(n), where n is the length of the string \textit{moves}
SpaceO(1) auxiliary

Pattern: Hash Map

Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 657. Robot Return to Origin is filed here because the reference solution below belongs to the algorithm family this hub collects, even though its LeetCode tags point elsewhere.

The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.

Related problems

Frequently asked questions

How hard is LeetCode 657. Robot Return to Origin?
LeetCode 657. Robot Return to Origin is rated Easy on LeetCode.
What is the time complexity of LeetCode 657. Robot Return to Origin?
The Python solution on this page runs in O(n), where n is the length of the string \textit{moves}.
What is the space complexity of LeetCode 657. Robot Return to Origin?
The Python solution on this page uses O(1) auxiliary space.
What topics does LeetCode 657. Robot Return to Origin cover?
LeetCode 657. Robot Return to Origin is tagged String and Simulation on LeetCode.

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