MediumNo. 1922

Count Good Numbers — LeetCode 1922 Python Solution

Topics
Recursion, Math
Reading time
2 min

The problem

A digit string is good if the digits (0-indexed) at even indices are even and the digits at odd indices are prime (2, 3, 5, or 7). For example, "2582" is good because the digits (2 and 8) at even positions are even and the digits (5 and 2) at odd positions are prime.

Example

Input
n = 1
Output
5
Explanation
The good numbers of length 1 are "0", "2", "4", "6", "8".

Python solution

PythonSolution
class Solution:
    def countGoodNumbers(self, n: int) -> int:
        mod = 10**9 + 7
        return pow(5, (n + 1) >> 1, mod) * pow(4, n >> 1, mod) % mod

Complexity

Time
O(log n)
Space · auxiliary
O(1)

Pattern: Math and Number Theory

Find the closed form, the invariant, or the modular identity — and skip the loop entirely. LeetCode 1922. Count Good Numbers is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Math.

The math and number theory guide has the Python template for the pattern and the 485 LeetCode problems that use it.

Related problems

Related problems
No.ProblemDifficulty
0002Add Two NumbersMedium
0050Pow(x, n)Medium
0060Permutation SequenceHard
0273Integer to English WordsHard
0326Power of ThreeEasy
0390Elimination GameMedium

Frequently asked questions

How hard is LeetCode 1922. Count Good Numbers?

LeetCode 1922. Count Good Numbers is rated Medium on LeetCode.

What is the time complexity of LeetCode 1922. Count Good Numbers?

The Python solution on this page runs in O(log n).

What is the space complexity of LeetCode 1922. Count Good Numbers?

The Python solution on this page uses O(1) auxiliary space.

What topics does LeetCode 1922. Count Good Numbers cover?

LeetCode 1922. Count Good Numbers is tagged Recursion and Math on LeetCode.

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