Power of Three — LeetCode 326 Python Solution
EasyRecursionMath
- Problem
- #326
- Pattern
- Math and Number Theory
- Reading time
- 2 min
- Source
- leetcode.com
The problem
Given an integer n, return true if it is a power of three. Otherwise, return false.
Example
- Input
- n = 27
- Output
- true
- Explanation
- 27 = 33
Python solution
Python
class Solution:
def isPowerOfThree(self, n: int) -> bool:
while n > 2:
if n % 3:
return False
n //= 3
return n == 1Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) or O(1) |
| Space | O(1) auxiliary |
Pattern: Math and Number Theory
Find the closed form, the invariant, or the modular identity — and skip the loop entirely. LeetCode 326. Power of Three is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Math.
The math and number theory guide has the Python template for the pattern and the 485 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 326. Power of Three?
- LeetCode 326. Power of Three is rated Easy on LeetCode.
- What topics does LeetCode 326. Power of Three cover?
- LeetCode 326. Power of Three is tagged Recursion and Math on LeetCode.