Number of Burgers with No Waste of Ingredients — LeetCode 1276 Python Solution
- Problem
- #1276
- Pattern
- Math and Number Theory
- Reading time
- 2 min
- Source
- leetcode.com
The problem
Given two integers tomatoSlices and cheeseSlices. The ingredients of different burgers are as follows: Jumbo Burger: 4 tomato slices and 1 cheese slice.
Example
- Input
- tomatoSlices = 16, cheeseSlices = 7
- Output
- [1,6]
Python solution
class Solution:
def numOfBurgers(self, tomatoSlices: int, cheeseSlices: int) -> List[int]:
k = 4 * cheeseSlices - tomatoSlices
y = k // 2
x = cheeseSlices - y
return [] if k % 2 or y < 0 or x < 0 else [x, y]Complexity
| Measure | Complexity |
|---|---|
| Time | O(1) |
| Space | O(1) auxiliary |
Pattern: Math and Number Theory
Find the closed form, the invariant, or the modular identity — and skip the loop entirely. LeetCode 1276. Number of Burgers with No Waste of Ingredients is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Math.
The math and number theory guide has the Python template for the pattern and the 485 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1276. Number of Burgers with No Waste of Ingredients?
- LeetCode 1276. Number of Burgers with No Waste of Ingredients is rated Medium on LeetCode.
- What is the time complexity of LeetCode 1276. Number of Burgers with No Waste of Ingredients?
- The Python solution on this page runs in O(1).
- What is the space complexity of LeetCode 1276. Number of Burgers with No Waste of Ingredients?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 1276. Number of Burgers with No Waste of Ingredients cover?
- LeetCode 1276. Number of Burgers with No Waste of Ingredients is tagged Math on LeetCode.