Reverse Integer — LeetCode 7 Python Solution

MediumMath
Problem
#7
Reading time
2 min

The problem

Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.

Example

Input
x = 123
Output
321

Python solution

Python
class Solution:
    def reverse(self, x: int) -> int:
        ans = 0
        mi, mx = -(2**31), 2**31 - 1
        while x:
            if ans < mi // 10 + 1 or ans > mx // 10:
                return 0
            y = x % 10
            if x < 0 and y > 0:
                y -= 10
            ans = ans * 10 + y
            x = (x - y) // 10
        return ans

Complexity

MeasureComplexity
TimeO(\log |x|), where |x| is the absolute value of x
SpaceO(1) auxiliary

Pattern: Math and Number Theory

Find the closed form, the invariant, or the modular identity — and skip the loop entirely. LeetCode 7. Reverse Integer is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Math.

The math and number theory guide has the Python template for the pattern and the 485 LeetCode problems that use it.

Related problems

On a study list

This problem is on NeetCode 150.

Frequently asked questions

How hard is LeetCode 7. Reverse Integer?
LeetCode 7. Reverse Integer is rated Medium on LeetCode.
What is the time complexity of LeetCode 7. Reverse Integer?
The Python solution on this page runs in O(\log |x|), where |x| is the absolute value of x.
What is the space complexity of LeetCode 7. Reverse Integer?
The Python solution on this page uses O(1) auxiliary space.
What topics does LeetCode 7. Reverse Integer cover?
LeetCode 7. Reverse Integer is tagged Math on LeetCode.

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