Greatest Sum Divisible by Three — LeetCode 1262 Python Solution

MediumGreedyArrayDynamic ProgrammingSorting
Problem
#1262
Pattern
Greedy
Reading time
2 min

The problem

Given an integer array nums, return the maximum possible sum of elements of the array such that it is divisible by three.

Example

Input
nums = [3,6,5,1,8]
Output
18
Explanation
Pick numbers 3, 6, 1 and 8 their sum is 18 (maximum sum divisible by 3).

Python solution

Python
class Solution:
    def maxSumDivThree(self, nums: List[int]) -> int:
        n = len(nums)
        f = [[-inf] * 3 for _ in range(n + 1)]
        f[0][0] = 0
        for i, x in enumerate(nums, 1):
            for j in range(3):
                f[i][j] = max(f[i - 1][j], f[i - 1][(j - x) % 3] + x)
        return f[n][0]

Complexity

MeasureComplexity
TimeO(n)
SpaceO(n) auxiliary

Pattern: Greedy

Take the locally best option every time — when you can prove that never costs you later. LeetCode 1262. Greatest Sum Divisible by Three is filed here because LeetCode tags it Greedy, which is the vocabulary this hub collects.

The greedy guide has the Python template for the pattern and the 346 LeetCode problems that use it.

Related problems

Frequently asked questions

How hard is LeetCode 1262. Greatest Sum Divisible by Three?
LeetCode 1262. Greatest Sum Divisible by Three is rated Medium on LeetCode.
What is the time complexity of LeetCode 1262. Greatest Sum Divisible by Three?
The Python solution on this page runs in O(n).
What is the space complexity of LeetCode 1262. Greatest Sum Divisible by Three?
The Python solution on this page uses O(n) auxiliary space.
What topics does LeetCode 1262. Greatest Sum Divisible by Three cover?
LeetCode 1262. Greatest Sum Divisible by Three is tagged Greedy, Array, Dynamic Programming and Sorting on LeetCode.

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