Day of the Year — LeetCode 1154 Python Solution
EasyMathString
- Problem
- #1154
- Pattern
- Math and Number Theory
- Reading time
- 2 min
- Source
- leetcode.com
The problem
Given a string date representing a Gregorian calendar date formatted as YYYY-MM-DD, return the day number of the year.
Example
- Input
- date = "2019-01-09"
- Output
- 9
- Explanation
- Given date is the 9th day of the year in 2019.
Python solution
Python
class Solution:
def dayOfYear(self, date: str) -> int:
y, m, d = (int(s) for s in date.split('-'))
v = 29 if y % 400 == 0 or (y % 4 == 0 and y % 100) else 28
days = [31, v, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
return sum(days[: m - 1]) + dComplexity
| Measure | Complexity |
|---|---|
| Time | O(1) |
| Space | O(1) auxiliary |
Pattern: Math and Number Theory
Find the closed form, the invariant, or the modular identity — and skip the loop entirely. LeetCode 1154. Day of the Year is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Math.
The math and number theory guide has the Python template for the pattern and the 485 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1154. Day of the Year?
- LeetCode 1154. Day of the Year is rated Easy on LeetCode.
- What is the time complexity of LeetCode 1154. Day of the Year?
- The Python solution on this page runs in O(1).
- What is the space complexity of LeetCode 1154. Day of the Year?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 1154. Day of the Year cover?
- LeetCode 1154. Day of the Year is tagged Math and String on LeetCode.