Two Sum — LeetCode 1 Python Solution
- Problem
- #1
- Pattern
- Hash Map
- Reading time
- 2 min
- Source
- leetcode.com
The problem
Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target. You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example
- Input
- nums = [2,7,11,15], target = 9
- Output
- [0,1]
- Explanation
- Because nums[0] + nums[1] == 9, we return [0, 1].
Python solution
class Solution:
def twoSum(self, nums: List[int], target: int) -> List[int]:
d = {}
for i, x in enumerate(nums):
if (y := target - x) in d:
return [d[y], i]
d[x] = iComplexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(n) auxiliary |
Pattern: Hash Map
Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 1. Two Sum is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Hash Table.
The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.
Related problems
On study lists
This problem is on Blind 75, NeetCode 150, Grind 75 and Top Interview 150.
Frequently asked questions
- How hard is LeetCode 1. Two Sum?
- LeetCode 1. Two Sum is rated Easy on LeetCode.
- What is the time complexity of LeetCode 1. Two Sum?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 1. Two Sum?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 1. Two Sum cover?
- LeetCode 1. Two Sum is tagged Array and Hash Table on LeetCode.