Interval List Intersections — LeetCode 986 Python Solution
- Problem
- #986
- Pattern
- Two Pointers
- Reading time
- 3 min
- Source
- leetcode.com
The problem
You are given two lists of closed intervals, firstList and secondList, where firstList[i] = [starti, endi] and secondList[j] = [startj, endj]. Each list of intervals is pairwise disjoint and in sorted order.
Example
- Input
- firstList = [[0,2],[5,10],[13,23],[24,25]], secondList = [[1,5],[8,12],[15,24],[25,26]]
- Output
- [[1,2],[5,5],[8,10],[15,23],[24,24],[25,25]]
Python solution
class Solution:
def intervalIntersection(
self, firstList: List[List[int]], secondList: List[List[int]]
) -> List[List[int]]:
i = j = 0
ans = []
while i < len(firstList) and j < len(secondList):
s1, e1, s2, e2 = *firstList[i], *secondList[j]
l, r = max(s1, s2), min(e1, e2)
if l <= r:
ans.append([l, r])
if e1 < e2:
i += 1
else:
j += 1
return ansComplexity
| Measure | Complexity |
|---|---|
| Time | O(n) (after optional sort O(n log n)) |
| Space | O(1) auxiliary |
Pattern: Two Pointers
Use the order already in the input to discard half the search space at every step. LeetCode 986. Interval List Intersections is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Two Pointers.
The two pointers guide has the Python template for the pattern and the 201 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 986. Interval List Intersections?
- LeetCode 986. Interval List Intersections is rated Medium on LeetCode.
- What is the time complexity of LeetCode 986. Interval List Intersections?
- The Python solution on this page runs in O(n) (after optional sort O(n log n)).
- What is the space complexity of LeetCode 986. Interval List Intersections?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 986. Interval List Intersections cover?
- LeetCode 986. Interval List Intersections is tagged Array, Two Pointers and Line Sweep on LeetCode.