Leetcode #831: Masking Personal Information
In this guide, we solve Leetcode #831 Masking Personal Information in Python and focus on the core idea that makes the solution efficient.
You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.
Problem Statement
You are given a personal information string s, representing either an email address or a phone number. Return the masked personal information using the below rules.
Quick Facts
- Difficulty: Medium
- Premium: No
- Tags: String
Intuition
We need to scan characters while tracking positions or counts.
A simple state machine keeps the logic precise.
Approach
Iterate through the string once and update the state for each character.
Use a map or array if you need fast lookups.
Steps:
- Iterate through characters.
- Maintain necessary state.
- Build or validate the output.
Example
Input: s = "LeetCode@LeetCode.com"
Output: "l*****e@leetcode.com"
Explanation: s is an email address.
The name and domain are converted to lowercase, and the middle of the name is replaced by 5 asterisks.
Python Solution
class Solution:
def maskPII(self, s: str) -> str:
if s[0].isalpha():
s = s.lower()
return s[0] + '*****' + s[s.find('@') - 1 :]
s = ''.join(c for c in s if c.isdigit())
cnt = len(s) - 10
suf = '***-***-' + s[-4:]
return suf if cnt == 0 else f'+{"*" * cnt}-{suf}'
Complexity
The time complexity is , and the space complexity is , where is the length of the string . The space complexity is , where is the length of the string .
Edge Cases and Pitfalls
Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.
Summary
This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.