Range Addition — LeetCode 370 Python Solution

MediumLeetCode PremiumArrayPrefix Sum
Problem
#370
Pattern
Prefix Sum
Reading time
2 min

The problem

You are given an integer length and an array updates where updates[i] = [startIdxi, endIdxi, inci]. You have an array arr of length length with all zeros, and you have some operation to apply on arr.

Example

Input
length = 5, updates = [[1,3,2],[2,4,3],[0,2,-2]]
Output
[-2,0,3,5,3]

Python solution

Python
class Solution:
    def getModifiedArray(self, length: int, updates: List[List[int]]) -> List[int]:
        d = [0] * length
        for l, r, c in updates:
            d[l] += c
            if r + 1 < length:
                d[r + 1] -= c
        return list(accumulate(d))

Complexity

MeasureComplexity
TimeO(n)
SpaceO(n) auxiliary

Pattern: Prefix Sum

Precompute running totals once so any range query becomes a single subtraction. LeetCode 370. Range Addition is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Prefix Sum.

The prefix sum guide has the Python template for the pattern and the 157 LeetCode problems that use it.

Related problems

Frequently asked questions

How hard is LeetCode 370. Range Addition?
LeetCode 370. Range Addition is rated Medium on LeetCode.
What is the time complexity of LeetCode 370. Range Addition?
The Python solution on this page runs in O(n).
What is the space complexity of LeetCode 370. Range Addition?
The Python solution on this page uses O(n) auxiliary space.
What topics does LeetCode 370. Range Addition cover?
LeetCode 370. Range Addition is tagged Array and Prefix Sum on LeetCode.
Is LeetCode 370. Range Addition a premium problem?
Yes. LeetCode 370. Range Addition is a LeetCode Premium problem, so the full statement and test cases require a paid LeetCode subscription.

Stuck on problems like this in a live interview?

Stealth Interview is a desktop app for macOS and Windows. It reads the problem off your screen and returns a working solution with a step-by-step explanation and its time and space complexity — invisible to screen sharing.

Get Stealth Interview