How hard is LeetCode 2879. Display the First Three Rows?

LeetCode 2879. Display the First Three Rows is rated Easy on LeetCode.

What topics does LeetCode 2879. Display the First Three Rows cover?

LeetCode 2879. Display the First Three Rows is tagged Pandas on LeetCode.

EasyNo. 2879

Display the First Three Rows — LeetCode 2879 Python Solution

Topics: Pandas
Reading time: 2 min
Source: leetcode.com

Table schema

SQLTable schema

DataFrame: employees +-------------+--------+ | Column Name | Type | +-------------+--------+ | employee_id | int | | name | object | | department | object | | salary | int | +-------------+--------+ Write a solution to display the first 3 rows of this DataFrame.

Example

SQLExample

DataFrame: employees
+-------------+--------+
| Column Name | Type   |
+-------------+--------+
| employee_id | int    |
| name        | object |
| department  | object |
| salary      | int    |
+-------------+--------+

Python solution

PythonSolution

import pandas as pd


def selectFirstRows(employees: pd.DataFrame) -> pd.DataFrame:
    return employees.head(3)

Complexity

Time: O(n)
Space · auxiliary: O(1) to O(n)

Related problems
No.	Problem	Difficulty
2877	Create a DataFrame from List	Easy
2874	Maximum Value of an Ordered Triplet II	Medium
2873	Maximum Value of an Ordered Triplet I	Easy
0057	Insert Interval	Medium
0192	Word Frequency	Medium
0193	Valid Phone Numbers	Easy

Frequently asked questions

How hard is LeetCode 2879. Display the First Three Rows?: LeetCode 2879. Display the First Three Rows is rated Easy on LeetCode.
What topics does LeetCode 2879. Display the First Three Rows cover?: LeetCode 2879. Display the First Three Rows is tagged Pandas on LeetCode.

Stuck on problems like this in a live interview?

Stealth Interview is a desktop app for macOS and Windows. It reads the problem off your screen and returns a working solution with a step-by-step explanation and its time and space complexity, invisible to screen sharing.

Download for Mac Download for Windows

Free to download. Check it runs on your machine, then pick a plan.

90%Subscription

python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

Technical interview · 45 minsolution.pyShared editor · Python 3Longest substring without repeatsMediumGiven a string s, return the length of the longest contiguous substring in which every character is unique.s = "abcabcbb"
→ 31def length_of_longest_substring(s: str) -> int:2 last_seen = {}3 left = best = 04 for right, ch in enumerate(s):5 if ch in last_seen and last_seen[ch] >= left:

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 Terra

Transcribing...

90%Subscription

python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 TerraClear chat

Transcribing...

QuitEscHide+QCapture+PCrop+OSubmit+EnterPress to get answerLeft/Right+Up/Down+

90%Subscription

python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 TerraClear chat

Transcribing...

Primary display

QuitEscHide+QCapture+PCrop+OSubmit+EnterPress to get answerLeft/Right+Up/Down+

Table schema

Example

Python solution

Complexity

Related problems

Frequently asked questions

Stuck on problems like this in a live interview?

Approach

Approach

Approach