Check if a String Is an Acronym of Words — LeetCode 2828 Python Solution
- Problem
- #2828
- Pattern
- Hash Map
- Reading time
- 2 min
- Source
- leetcode.com
The problem
Given an array of strings words and a string s, determine if s is an acronym of words. The string s is considered an acronym of words if it can be formed by concatenating the first character of each string in words in order.
Example
- Input
- words = ["alice","bob","charlie"], s = "abc"
- Output
- true
- Explanation
- The first character in the words "alice", "bob", and "charlie" are 'a', 'b', and 'c', respectively. Hence, s = "abc" is the acronym.
Python solution
class Solution:
def isAcronym(self, words: List[str], s: str) -> bool:
return "".join(w[0] for w in words) == sComplexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(n) auxiliary |
Pattern: Hash Map
Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 2828. Check if a String Is an Acronym of Words is filed here because the reference solution below belongs to the algorithm family this hub collects, even though its LeetCode tags point elsewhere.
The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 2828. Check if a String Is an Acronym of Words?
- LeetCode 2828. Check if a String Is an Acronym of Words is rated Easy on LeetCode.
- What is the time complexity of LeetCode 2828. Check if a String Is an Acronym of Words?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 2828. Check if a String Is an Acronym of Words?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 2828. Check if a String Is an Acronym of Words cover?
- LeetCode 2828. Check if a String Is an Acronym of Words is tagged Array and String on LeetCode.