Wiggle Sort — LeetCode 280 Python Solution
MediumLeetCode PremiumGreedyArraySorting
- Problem
- #280
- Pattern
- Greedy
- Reading time
- 2 min
- Source
- leetcode.com
The problem
Given an integer array nums, reorder it such that nums[0] <= nums[1] >= nums[2] <= nums[3].... You may assume the input array always has a valid answer.
Example
- Input
- nums = [3,5,2,1,6,4]
- Output
- [3,5,1,6,2,4]
- Explanation
- [1,6,2,5,3,4] is also accepted.
Python solution
Python
class Solution:
def wiggleSort(self, nums: List[int]) -> None:
"""
Do not return anything, modify nums in-place instead.
"""
for i in range(1, len(nums)):
if (i % 2 == 1 and nums[i] < nums[i - 1]) or (
i % 2 == 0 and nums[i] > nums[i - 1]
):
nums[i], nums[i - 1] = nums[i - 1], nums[i]Complexity
| Measure | Complexity |
|---|---|
| Time | O(n log n) |
| Space | O(1) to O(n) auxiliary |
Pattern: Greedy
Take the locally best option every time — when you can prove that never costs you later. LeetCode 280. Wiggle Sort is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Greedy.
The greedy guide has the Python template for the pattern and the 346 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 280. Wiggle Sort?
- LeetCode 280. Wiggle Sort is rated Medium on LeetCode.
- What topics does LeetCode 280. Wiggle Sort cover?
- LeetCode 280. Wiggle Sort is tagged Greedy, Array and Sorting on LeetCode.
- Is LeetCode 280. Wiggle Sort a premium problem?
- Yes. LeetCode 280. Wiggle Sort is a LeetCode Premium problem, so the full statement and test cases require a paid LeetCode subscription.