Status of Flight Tickets — LeetCode 2793 Python Solution
HardLeetCode PremiumDatabase
- Problem
- #2793
- Reading time
- 4 min
- Source
- leetcode.com
Table schema
SQL
Table: Flights +-------------+------+ | Column Name | Type | +-------------+------+ | flight_id | int | | capacity | int | +-------------+------+ flight_id column contains distinct values. Each row of this table contains flight id and capacity.Example
SQL
+-------------+------+
| Column Name | Type |
+-------------+------+
| flight_id | int |
| capacity | int |
+-------------+------+
flight_id column contains distinct values.
Each row of this table contains flight id and capacity.Python solution
Python
import duckdb
import pandas as pd
def solution(passengers: pd.DataFrame) -> pd.DataFrame:
con = duckdb.connect()
con.register("Passengers", passengers)
return con.execute("""SELECT
passenger_id,
IF(
(
RANK() OVER (
PARTITION BY flight_id
ORDER BY booking_time
)
) <= capacity,
'Confirmed',
'Waitlist'
) AS Status
FROM
Passengers
JOIN Flights USING (flight_id)
ORDER BY passenger_id;""").df()Complexity
| Measure | Complexity |
|---|---|
| Time | O(n log n) (typical) |
| Space | O(n) auxiliary |
Related problems
Frequently asked questions
- How hard is LeetCode 2793. Status of Flight Tickets?
- LeetCode 2793. Status of Flight Tickets is rated Hard on LeetCode.
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- LeetCode 2793. Status of Flight Tickets is tagged Database on LeetCode.
- Is LeetCode 2793. Status of Flight Tickets a premium problem?
- Yes. LeetCode 2793. Status of Flight Tickets is a LeetCode Premium problem, so the full statement and test cases require a paid LeetCode subscription.