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Leetcode #2696: Minimum String Length After Removing Substrings

In this guide, we solve Leetcode #2696 Minimum String Length After Removing Substrings in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

You are given a string s consisting only of uppercase English letters. You can apply some operations to this string where, in one operation, you can remove any occurrence of one of the substrings "AB" or "CD" from s.

Quick Facts

  • Difficulty: Easy
  • Premium: No
  • Tags: Stack, String, Simulation

Intuition

The problem has a natural nested or last-in-first-out structure.

A stack lets us resolve matches in the correct order as we scan.

Approach

Push items as they appear and pop when you can finalize a decision.

The stack captures the unresolved part of the input.

Steps:

  • Push elements as you scan.
  • Pop when a rule or match is satisfied.
  • Use the stack to compute results.

Example

Input: s = "ABFCACDB" Output: 2 Explanation: We can do the following operations: - Remove the substring "ABFCACDB", so s = "FCACDB". - Remove the substring "FCACDB", so s = "FCAB". - Remove the substring "FCAB", so s = "FC". So the resulting length of the string is 2. It can be shown that it is the minimum length that we can obtain.

Python Solution

class Solution: def minLength(self, s: str) -> int: stk = [""] for c in s: if (c == "B" and stk[-1] == "A") or (c == "D" and stk[-1] == "C"): stk.pop() else: stk.append(c) return len(stk) - 1

Complexity

The time complexity is O(n)O(n)O(n), and the space complexity is O(n)O(n)O(n), where nnn is the length of the string sss. The space complexity is O(n)O(n)O(n), where nnn is the length of the string sss.

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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