Find Active Users — LeetCode 2688 Python Solution

MediumLeetCode PremiumDatabase
Problem
#2688
Reading time
5 min

Table schema

SQL
Table: Users +-------------+----------+ | Column Name | Type | +-------------+----------+ | user_id | int | | item | varchar | | created_at | datetime | | amount | int | +-------------+----------+ This table may contain duplicate records. Each row includes the user ID, the purchased item, the date of purchase, and the purchase amount.

Example

SQL
+-------------+----------+ 
| Column Name | Type     | 
+-------------+----------+ 
| user_id     | int      | 
| item        | varchar  |
| created_at  | datetime |
| amount      | int      |
+-------------+----------+
This table may contain duplicate records. 
Each row includes the user ID, the purchased item, the date of purchase, and the purchase amount.

Python solution

Python
import duckdb
import pandas as pd

# Pass input tables as keyword arguments matching the SQL table names.
def solution(**tables) -> pd.DataFrame:
    con = duckdb.connect()
    for name, df in tables.items():
        con.register(name, df)
    return con.execute("""SELECT DISTINCT
    user_id
FROM Users
WHERE
    user_id IN (
        SELECT
            user_id
        FROM
            (
                SELECT
                    user_id,
                    created_at,
                    LAG(created_at, 1) OVER (
                        PARTITION BY user_id
                        ORDER BY created_at
                    ) AS prev_created_at
                FROM Users
            ) AS t
        WHERE DATEDIFF(created_at, prev_created_at) <= 7
    );""").df()

Complexity

MeasureComplexity
TimeO(n log n) (typical)
SpaceO(n) auxiliary

Related problems

Frequently asked questions

How hard is LeetCode 2688. Find Active Users?
LeetCode 2688. Find Active Users is rated Medium on LeetCode.
What topics does LeetCode 2688. Find Active Users cover?
LeetCode 2688. Find Active Users is tagged Database on LeetCode.
Is LeetCode 2688. Find Active Users a premium problem?
Yes. LeetCode 2688. Find Active Users is a LeetCode Premium problem, so the full statement and test cases require a paid LeetCode subscription.

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