Leetcode #2650: Design Cancellable Function
In this guide, we solve Leetcode #2650 Design Cancellable Function in Python and focus on the core idea that makes the solution efficient.
You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.
Problem Statement
Sometimes you have a long running task, and you may wish to cancel it before it completes. To help with this goal, write a function cancellable that accepts a generator object and returns an array of two values: a cancel function and a promise.
Quick Facts
- Difficulty: Hard
- Premium: No
- Tags: JavaScript
Intuition
The constraints allow a direct scan that keeps only the essential state.
By translating the requirements into a clean loop, the logic stays easy to reason about.
Approach
Iterate through the data once, updating the state needed to compute the answer.
Return the final state after the traversal is complete.
Steps:
- Parse the input.
- Iterate and update state.
- Return the computed answer.
Example
function* tasks() {
const val = yield new Promise(resolve => resolve(2 + 2));
yield new Promise(resolve => setTimeout(resolve, 100));
return val + 1; // calculation shouldn't be done.
}
const [cancel, promise] = cancellable(tasks());
setTimeout(cancel, 50);
promise.catch(console.log); // logs "Cancelled" at t=50ms
Python Solution
# TODO: add Python solution
Complexity
The time complexity is O(n). The space complexity is O(1) to O(n).
Edge Cases and Pitfalls
Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.
Summary
This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.