How hard is LeetCode 2527. Find Xor-Beauty of Array?

LeetCode 2527. Find Xor-Beauty of Array is rated Medium on LeetCode.

What is the time complexity of LeetCode 2527. Find Xor-Beauty of Array?

The Python solution on this page runs in O(n).

What is the space complexity of LeetCode 2527. Find Xor-Beauty of Array?

The Python solution on this page uses O(1), where n is the length of the array auxiliary space.

What topics does LeetCode 2527. Find Xor-Beauty of Array cover?

LeetCode 2527. Find Xor-Beauty of Array is tagged Bit Manipulation, Array and Math on LeetCode.

MediumNo. 2527

Find Xor-Beauty of Array — LeetCode 2527 Python Solution

Pattern: Bit Manipulation
Topics: Bit Manipulation, Array, Math
Reading time: 2 min
Source: leetcode.com

The problem

You are given a 0-indexed integer array nums. The effective value of three indices i, j, and k is defined as ((nums[i] | nums[j]) & nums[k]).

Example

Input: nums = [1,4]
Output: 5
Explanation: The triplets and their corresponding effective values are listed below:

Python solution

PythonSolution

class Solution:
    def xorBeauty(self, nums: List[int]) -> int:
        return reduce(xor, nums)

Complexity

Time: O(n)
Space · auxiliary: O(1)where n is the length of the array

Pattern: Bit Manipulation

Use XOR, masks and the low-bit trick to replace whole data structures with an integer. LeetCode 2527. Find Xor-Beauty of Array is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Bit Manipulation.

The bit manipulation guide has the Python template for the pattern and the 194 LeetCode problems that use it.

Related problems
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0477	Total Hamming Distance	Medium
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0810	Chalkboard XOR Game	Hard
1835	Find XOR Sum of All Pairs Bitwise AND	Hard
2317	Maximum XOR After Operations	Medium
0029	Divide Two Integers	Medium

Frequently asked questions

How hard is LeetCode 2527. Find Xor-Beauty of Array?: LeetCode 2527. Find Xor-Beauty of Array is rated Medium on LeetCode.
What is the time complexity of LeetCode 2527. Find Xor-Beauty of Array?: The Python solution on this page runs in O(n).
What is the space complexity of LeetCode 2527. Find Xor-Beauty of Array?: The Python solution on this page uses O(1), where n is the length of the array auxiliary space.
What topics does LeetCode 2527. Find Xor-Beauty of Array cover?: LeetCode 2527. Find Xor-Beauty of Array is tagged Bit Manipulation, Array and Math on LeetCode.

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python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

Technical interview · 45 minsolution.pyShared editor · Python 3Longest substring without repeatsMediumGiven a string s, return the length of the longest contiguous substring in which every character is unique.s = "abcabcbb"
→ 31def length_of_longest_substring(s: str) -> int:2 last_seen = {}3 left = best = 04 for right, ch in enumerate(s):5 if ch in last_seen and last_seen[ch] >= left:

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 Terra

Transcribing...

90%Subscription

python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 TerraClear chat

Transcribing...

QuitEscHide+QCapture+PCrop+OSubmit+EnterPress to get answerLeft/Right+Up/Down+

90%Subscription

python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 TerraClear chat

Transcribing...

Primary display

QuitEscHide+QCapture+PCrop+OSubmit+EnterPress to get answerLeft/Right+Up/Down+

The problem

Example

Python solution

Complexity

Pattern: Bit Manipulation

Related problems

Frequently asked questions

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Approach

Approach

Approach