Stealth Interview
  • Features
  • Pricing
  • Blog
  • Login
  • Sign up

Leetcode #2449: Minimum Number of Operations to Make Arrays Similar

In this guide, we solve Leetcode #2449 Minimum Number of Operations to Make Arrays Similar in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

You are given two positive integer arrays nums and target, of the same length. In one operation, you can choose any two distinct indices i and j where 0 <= i, j < nums.length and: set nums[i] = nums[i] + 2 and set nums[j] = nums[j] - 2.

Quick Facts

  • Difficulty: Hard
  • Premium: No
  • Tags: Greedy, Array, Sorting

Intuition

A locally optimal choice leads to a globally optimal result for this structure.

That means we can commit to decisions as we scan without backtracking.

Approach

Sort or preprocess if needed, then repeatedly take the best available local choice.

Maintain the minimal state necessary to validate the greedy decision.

Steps:

  • Sort or preprocess as needed.
  • Iterate and pick the best local option.
  • Track the current solution.

Example

Input: nums = [8,12,6], target = [2,14,10] Output: 2 Explanation: It is possible to make nums similar to target in two operations: - Choose i = 0 and j = 2, nums = [10,12,4]. - Choose i = 1 and j = 2, nums = [10,14,2]. It can be shown that 2 is the minimum number of operations needed.

Python Solution

class Solution: def makeSimilar(self, nums: List[int], target: List[int]) -> int: nums.sort(key=lambda x: (x & 1, x)) target.sort(key=lambda x: (x & 1, x)) return sum(abs(a - b) for a, b in zip(nums, target)) // 4

Complexity

The time complexity is O(n×log⁡n)O(n \times \log n)O(n×logn), where nnn is the length of the array numsnumsnums. The space complexity is O(1) to O(n).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


Ace your next coding interview

We're here to help you ace your next coding interview.

Subscribe
Stealth Interview
© 2026 Stealth Interview®Stealth Interview is a registered trademark. All rights reserved.
Product
  • Blog
  • Pricing
Company
  • Terms of Service
  • Privacy Policy