Percentage of Letter in String — LeetCode 2278 Python Solution
EasyString
- Problem
- #2278
- Pattern
- Hash Map
- Reading time
- 2 min
- Source
- leetcode.com
The problem
Given a string s and a character letter, return the percentage of characters in s that equal letter rounded down to the nearest whole percent.
Example
- Input
- s = "foobar", letter = "o"
- Output
- 33
- Explanation
- The percentage of characters in s that equal the letter 'o' is 2 / 6 * 100% = 33% when rounded down, so we return 33.
Python solution
Python
class Solution:
def percentageLetter(self, s: str, letter: str) -> int:
return s.count(letter) * 100 // len(s)Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(1) to O(n) auxiliary |
Pattern: Hash Map
Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 2278. Percentage of Letter in String is filed here because the reference solution below belongs to the algorithm family this hub collects, even though its LeetCode tags point elsewhere.
The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 2278. Percentage of Letter in String?
- LeetCode 2278. Percentage of Letter in String is rated Easy on LeetCode.
- What topics does LeetCode 2278. Percentage of Letter in String cover?
- LeetCode 2278. Percentage of Letter in String is tagged String on LeetCode.