Sort Even and Odd Indices Independently — LeetCode 2164 Python Solution
EasyArraySorting
- Problem
- #2164
- Pattern
- Sorting
- Reading time
- 2 min
- Source
- leetcode.com
The problem
You are given a 0-indexed integer array nums. Rearrange the values of nums according to the following rules: Sort the values at odd indices of nums in non-increasing order.
Example
- Input
- nums = [4,1,2,3]
- Output
- [2,3,4,1]
- Explanation
- First, we sort the values present at odd indices (1 and 3) in non-increasing order.
Python solution
Python
class Solution:
def sortEvenOdd(self, nums: List[int]) -> List[int]:
a = sorted(nums[::2])
b = sorted(nums[1::2], reverse=True)
nums[::2] = a
nums[1::2] = b
return numsComplexity
| Measure | Complexity |
|---|---|
| Time | O(n \log n) |
| Space | O(n) auxiliary |
Pattern: Sorting
Spend O(n log n) once to buy an ordering that makes the rest of the problem trivial. LeetCode 2164. Sort Even and Odd Indices Independently is filed here because LeetCode tags it Sorting, which is the vocabulary this hub collects.
The sorting guide has the Python template for the pattern and the 401 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 2164. Sort Even and Odd Indices Independently?
- LeetCode 2164. Sort Even and Odd Indices Independently is rated Easy on LeetCode.
- What is the time complexity of LeetCode 2164. Sort Even and Odd Indices Independently?
- The Python solution on this page runs in O(n \log n).
- What is the space complexity of LeetCode 2164. Sort Even and Odd Indices Independently?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 2164. Sort Even and Odd Indices Independently cover?
- LeetCode 2164. Sort Even and Odd Indices Independently is tagged Array and Sorting on LeetCode.