Redistribute Characters to Make All Strings Equal — LeetCode 1897 Python Solution
- Problem
- #1897
- Pattern
- Hash Map
- Reading time
- 2 min
- Source
- leetcode.com
The problem
You are given an array of strings words (0-indexed). In one operation, pick two distinct indices i and j, where words[i] is a non-empty string, and move any character from words[i] to any position in words[j].
Example
- Input
- words = ["abc","aabc","bc"]
- Output
- true
- Explanation
- Move the first 'a' in words[1] to the front of words[2],
Python solution
class Solution:
def makeEqual(self, words: List[str]) -> bool:
cnt = Counter()
for w in words:
for c in w:
cnt[c] += 1
n = len(words)
return all(v % n == 0 for v in cnt.values())Complexity
| Measure | Complexity |
|---|---|
| Time | O(L) |
| Space | O(|\Sigma|) auxiliary |
Pattern: Hash Map
Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 1897. Redistribute Characters to Make All Strings Equal is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Hash Table and Counting.
The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1897. Redistribute Characters to Make All Strings Equal?
- LeetCode 1897. Redistribute Characters to Make All Strings Equal is rated Easy on LeetCode.
- What is the time complexity of LeetCode 1897. Redistribute Characters to Make All Strings Equal?
- The Python solution on this page runs in O(L).
- What is the space complexity of LeetCode 1897. Redistribute Characters to Make All Strings Equal?
- The Python solution on this page uses O(|\Sigma|) auxiliary space.
- What topics does LeetCode 1897. Redistribute Characters to Make All Strings Equal cover?
- LeetCode 1897. Redistribute Characters to Make All Strings Equal is tagged Hash Table, String and Counting on LeetCode.