Determine if String Halves Are Alike — LeetCode 1704 Python Solution

EasyStringCounting
Problem
#1704
Pattern
Hash Map
Reading time
2 min

The problem

You are given a string s of even length. Split this string into two halves of equal lengths, and let a be the first half and b be the second half.

Example

Input
s = "book"
Output
true
Explanation
a = "bo" and b = "ok". a has 1 vowel and b has 1 vowel. Therefore, they are alike.

Python solution

Python
class Solution:
    def halvesAreAlike(self, s: str) -> bool:
        cnt, n = 0, len(s) >> 1
        vowels = set('aeiouAEIOU')
        for i in range(n):
            cnt += s[i] in vowels
            cnt -= s[i + n] in vowels
        return cnt == 0

Complexity

MeasureComplexity
TimeO(n), where n is the length of the string
SpaceO(C), where C is the number of vowel characters auxiliary

Pattern: Hash Map

Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 1704. Determine if String Halves Are Alike is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Counting.

The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.

Related problems

Frequently asked questions

How hard is LeetCode 1704. Determine if String Halves Are Alike?
LeetCode 1704. Determine if String Halves Are Alike is rated Easy on LeetCode.
What is the time complexity of LeetCode 1704. Determine if String Halves Are Alike?
The Python solution on this page runs in O(n), where n is the length of the string.
What is the space complexity of LeetCode 1704. Determine if String Halves Are Alike?
The Python solution on this page uses O(C), where C is the number of vowel characters auxiliary space.
What topics does LeetCode 1704. Determine if String Halves Are Alike cover?
LeetCode 1704. Determine if String Halves Are Alike is tagged String and Counting on LeetCode.

Stuck on problems like this in a live interview?

Stealth Interview is a desktop app for macOS and Windows. It reads the problem off your screen and returns a working solution with a step-by-step explanation and its time and space complexity — invisible to screen sharing.

Get Stealth Interview